Receiving Systems
Receiving Systems
Power Supplies
Prior to making "power-on" measurements on a switching power supply, you should be familiar with the supply because of the following:
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A constant frequency switching power supply regulator with an input voltage of 165 volts DC, and a switching frequency of 20 kHz, has an "ON" time of 27 microseconds when supplying 1 ampere to its load. What is the output voltage across the load?
From Alov:
Vo=V in x D,
D= T on x F
To find the output voltage across the load, we can use the formula for the average output voltage of a switching power supply:
Output Voltage = (ON Time / Switching Period) * Input Voltage
First, let's calculate the switching period:
Switching Period = 1 / Switching Frequency Switching Period = 1 / 20,000 Hz Switching Period ≈ 0.00005 seconds (50 microseconds)
Now, we can use the formula to calculate the output voltage:
Output Voltage = (27 microseconds / 50 microseconds) * 165 volts DC Output Voltage ≈ (0.54) * 165 volts DC Output Voltage ≈ 89.1 volts DC
Explanation: The switching power supply operates by rapidly turning ON and OFF its switching element (usually a transistor) at a high frequency (20 kHz in this case). The ON time is the duration for which the switching element is turned ON during each switching cycle.
The average output voltage across the load is calculated by dividing the ON time by the switching period (the time for one complete ON-OFF cycle) and then multiplying it by the input voltage.
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The circuit shown in Fig. 8C10 is the output of a switching power supply. Measuring from the junction of CR6, CR7 and L1 to ground with an oscilloscope, what waveform would you expect to see?
Switching power supplies operate at 20KHz and up, way above 60Hz US AC, 50Hz European AC and 400Hz ship and aircraft AC.
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With regard to the comparator shown in Fig. 8C11, the input is a sinusoid. Nominal high level output of the comparator is 4.5 volts. Choose the most correct statement regarding the input and output.
A comparator is an electronic device that compares the amplitude of two input signals and produces an output based on their relative levels. In this case, the input to the comparator is a sinusoidal waveform.
When the input waveform is a sinusoid, it goes through positive and negative zero crossings as it oscillates. The "positive zero crossing" refers to the point where the sinusoid changes direction from a negative value to zero and then becomes positive.
For the comparator output, the "leading edge" is the rising edge of the waveform. In this context, it means the point where the output transitions from a low voltage level to a high voltage level.
The statement indicates that the leading edge of the output waveform occurs 180 degrees after the positive zero crossing of the input waveform. This means that the output waveform rises to its high level after the input waveform crosses the positive zero point and continues to rise for half a cycle of the sinusoid.
Mnemonic: "POLE - Positive, Output, Leading, Edge"
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When monitoring the gate voltage of a power MOSFET in the switching power supply of a modern RADAR, you would expect to see the gate voltage change from "low" to "high" by how much?
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The nominal output high of the comparator shown in Fig. 8C11 is 4.5 volts. Choose the most correct statement which describes the trip points.
The formula to calculate voltage division is:
\(V_{tj} = V_{out} \times \frac{R_2}{(R_1 + R_2)}\)
So plugging in the values we can get
\(V_{tj} = 4.5V \times \frac{2Ω}{(5Ω + 2Ω )}\) \(V_{tj} = 4.5V \times 0.2855 = 1.285V\)
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