Ohms law involves 3 variables - Voltage (\(E\), for Electromotive force) Resistance (\(R\)), and Current (\(I\)). In a recent webcast, Gordon West suggested a simple method for remembering their order. He suggests that you think of \(E\) as an Eagle, \(I\) as an Igloo, and \(R\) as a Rabbit.

Any time \(E\) is on the left side, \(I\) and \(R\) are on the right side; the Igloo and the Rabbit are both on the ground, so they go next to each other (multiplication, or \(E=I\times R\)). If \(E\) is on the right side, then the Eagle is always on top (in the air). So Resistance is \(\frac{E}{I}\), because the Eagle is always above the Igloo. Current (\(I\)) is \(\frac{E}{R}\), because the eagle is always above the Rabbit. (Remember that \(\frac{E}{R}\) means \(E\) divided by \(R\))

This might help you remember the formulae for Ohms Law.

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Tags: ohm's law electrical current electromotive force (voltage) resistance

Ohms law involves 3 variables - Voltage (\(E\), for Electromotive force) Resistance (\(R\)), and Current (\(I\)). In a recent webcast, Gordon West suggested a simple method for remembering their order. He suggests that you think of \(E\) as an Eagle, \(I\) as an Igloo, and \(R\) as a Rabbit.

Any time \(E\) is on the left side, \(I\) and \(R\) are on the right side; the Igloo and the Rabbit are both on the ground, so they go next to each other (multiplication, or \(E=I\times R\)). If \(E\) is on the right side, then the Eagle is always on top (in the air). So Resistance is \(\frac{E}{I}\), because the Eagle is always above the Igloo. Current (\(I\)) is \(\frac{E}{R}\), because the eagle is always above the Rabbit. (Remember that \(\frac{E}{R}\) means \(E\) divided by \(R\))

This might help you remember the formulae for Ohms Law.

Last edited by kd7bbc. Register to edit

Tags: ohm's law electrical current electromotive force (voltage) resistance

Ohms law involves 3 variables - Voltage (\(E\), for Electromotive force) Resistance (\(R\)), and Current (\(I\)). In a recent webcast, Gordon West suggested a simple method for remembering their order. He suggests that you think of \(E\) as an Eagle, \(I\) as an Igloo, and \(R\) as a Rabbit.

Any time \(E\) is on the left side, \(I\) and \(R\) are on the right side; the Igloo and the Rabbit are both on the ground, so they go next to each other (multiplication, or \(E=I\times R\)). If \(E\) is on the right side, then the Eagle is always on top (in the air). So Resistance is \(\frac{E}{I}\), because the Eagle is always above the Igloo. Current (\(I\)) is \(\frac{E}{R}\), because the eagle is always above the Rabbit. (Remember that \(\frac{E}{R}\) means \(E\) divided by \(R\))

This might help you remember the formulae for Ohms Law.

Last edited by kd7bbc. Register to edit

Tags: ohm's law resistance electromotive force (voltage) electrical current

Ohms law involves 3 variables - Voltage (\(E\), for Electromotive force) Resistance (\(R\)), and Current (\(I\)). In a recent webcast, Gordon West suggested a simple method for remembering their order. He suggests that you think of \(E\) as an Eagle, \(I\) as an Igloo, and \(R\) as a Rabbit.

Any time \(E\) is on the left side, \(I\) and \(R\) are on the right side; the Igloo and the Rabbit are both on the ground, so they go next to each other (multiplication, or \(E=I\times R\)). If \(E\) is on the right side, then the Eagle is always on top (in the air). So Resistance is \(\frac{E}{I}\), because the Eagle is always above the Igloo. Current (\(I\)) is \(\frac{E}{R}\), because the eagle is always above the Rabbit. (Remember that \(\frac{E}{R}\) means \(E\) divided by \(R\))

This might help you remember the formulae for Ohms Law.

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Tags: math ohm's law resistance electrical current electromotive force (voltage)

\(E = I \times R\)

\(R = \frac{E}{I}\) \(=\) \(\frac{12}{1.5}\) = \(8\) ohms

See Ohm's Law on Wikipedia

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\(E = I \times R\)

\(R = \frac{E}{I}\) \(=\) \(\frac{12}{4}\) \(=\) \(3\) ohms

See Ohm's Law on Wikipedia

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\(E = I \times R\)

\(I = \frac{E}{R} = \frac{120}{80} = 1.5 \text{ amperes}\)

See Ohm's Law on Wikipedia

• E = Electromotive force (Volts)
• I = Intensity (Amperes)
• R = Resistance (Ohms)

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Tags: math ohm's law electromotive force (voltage) resistance electrical current

Voltage = Current \(\times\) Resistance

Which we can write as: \[E = I \times R\]

Where:

• \(E\) is the voltage applied to the circuit, in volts (V)
• \(I\) is the current flowing in the circuit, in amperes (A)
• \(R\) is the resistance in the circuit, in ohms (\(\Omega\))

In this case we have voltage and resistance and need to find current, so rearrange the equation: \begin{align} E &= I \times R\\ I &= \frac{E}{R}\\ \end{align}

Time to plug and chug! \begin{align} I &= \frac{200 \text{ V}}{100\ \Omega}\\ I &= 2 \text{ A}\\ \end{align}

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See Ohm's Law on Wikipedia

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\(E = I \times R\)

\(I = \frac{E}{R} = \frac{240}{24} = 10\) amperes

See Ohm's Law on Wikipedia

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This is an Ohm's law question. Remember

\(E = I \times R\)

\(E = 0.5 \text{ A} \times 2\ \Omega = 1 \text{ V}\)

See Ohm's Law on Wikipedia

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Tags: ohm's law math electrical current electromotive force (voltage) resistance

Ohm's Law is the relationship between voltage, current, and the resistance in a DC circuit. It can be represented in the equation:

\(E = I \times R\)

Where \(E\) is the voltage/electromotive force (\(E\)), \(I\) is the current (\(A\)), and \(R\) is the resistance (Ω).

If you have any two values in the equation you can find the third:

• \(E = I \times R\)
• \(R = \frac{E}{I}\) (obtained by dividing both sides by I)
• \(I = \frac{E}{R}\) (obtained by dividing both sides by R)

So for our equation:

• \(E = ?\)
• \(I = 1A\)
• \(R = 10Ω\)

\(E = I \times R = 10Ω \times 1A = 10V\)

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Tags: ohm's law math electrical current electromotive force (voltage) resistance

\(E = I \times R = 2 \times 10 = 20\) volts

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