Ohm's Law and Power.
Ohm's Law and Power.
If you have a hand-held transceiver which puts out 500 milliwatts, how many watts would this be?
A thousand milliwatts is one watt. Converting from milliwatts to watts: from small units to larger units, requires fewer digits, decimal point moves to the left by three positions, a thousand times less.
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What is the word used to describe the rate at which electrical energy is used?
If you have light bulbs marked 40 watts, 60 watts and 100 watts, which one will use electrical energy the fastest?
How fast does each one make the electrical utility meter on the side of your house spin ? The device with the highest wattage spins it the fastest.
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Power, expressed in watts = voltage, in volts, TIMES current, in amperes. P = E * I. Watts = volts * amperes. The watt describe how fast electrical energy is used.
Original copyright; explanations transcribed with permission from Francois VE2AAY, author of the ExHAMiner exam simulator. Do not copy without his permission.
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Power, expressed in watts = voltage, in volts, TIMES current, in amperes. P = E * I. Watts = volts * amperes. The watt describe how fast electrical energy is used.
Original copyright; explanations transcribed with permission from Francois VE2AAY, author of the ExHAMiner exam simulator. Do not copy without his permission.
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Which of the following two quantities should be multiplied together to find power?
Power, expressed in watts = voltage, in volts, TIMES current, in amperes. P = E * I. Watts = volts * amperes. The watt describe how fast electrical energy is used.
Original copyright; explanations transcribed with permission from Francois VE2AAY, author of the ExHAMiner exam simulator. Do not copy without his permission.
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Which two electrical units multiplied together give the unit "watts"?
Power, expressed in watts = voltage, in volts, TIMES current, in amperes. P = E * I. Watts = volts * amperes. The watt describe how fast electrical energy is used.
Original copyright; explanations transcribed with permission from Francois VE2AAY, author of the ExHAMiner exam simulator. Do not copy without his permission.
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A resistor in a circuit becomes very hot and starts to burn. This is because the resistor is dissipating too much:
Power is voltage times current, P = E * I. When current flows through a resistor, a 'voltage drop' ensues. Volts times amperes become watts. Power is dissipated as heat.
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High power resistors are usually large with heavy leads. The size aids the operation of the resistor by:
The resistor that could dissipate the most heat would be marked:
If a current of 2 amperes flows through a 50-ohm resistor, what is the voltage across the resistor?
Ohm's Law ( I = E / R ) becomes E = R*I when solving for E. Voltage = resistance times current. Volts = ohms * amperes. 50 ohms * 2 amperes = 100 volts.
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How is the current in a DC circuit calculated when the voltage and resistance are known?
How is the resistance in a DC circuit calculated when the voltage and current are known?
How is the voltage in a DC circuit calculated when the current and resistance are known?
If a 12-volt battery supplies 0.25 ampere to a circuit, what is the circuit's resistance?
Ohm's Law ( I = E / R ) becomes R = E / I when solving for R. Resistance is voltage divided by current. Ohms = volts / amperes. 12 volts / 0.25 amperes = 48 ohms.
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Calculate the value of resistance necessary to drop 100 volts with current flow of 0.8 milliamperes:
Ohm's Law ( I = E / R ) becomes R = E / I when solving for R. Resistance is voltage divided by current. Ohms = volts / amperes. 100 volts / 0.0008 amperes = 125 000 ohms = 125 kilohms. [ Note that volts divided by milliamperes is kilohm ]
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The voltage required to force a current of 4.4 amperes through a resistance of 50 ohms is:
Ohm's Law ( I = E / R ) becomes E = R*I when solving for E. Voltage is resistance times current. Volts = ohms * amperes. 50 ohms * 4.4 amperes = 220 volts.
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A lamp has a resistance of 30 ohms and a 6 volt battery is connected. The current flow will be:
What voltage would be needed to supply a current of 200 milliamperes, to operate an electric lamp which has a resistance of 25 ohms?
Ohm's Law ( I = E / R ) becomes E = R*I when solving for E. Voltage is resistance times current. Volts = ohms * amperes. 25 ohms * 0.200 amperes = 5 volts.
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The resistance of a circuit can be found by using one of the following:
If a 3 volt battery supplies 300 milliamperes to a circuit, the circuit resistance is:
Ohm's Law ( I = E / R ) becomes R = E / I when solving for R. Resistance is voltage divided by current. Ohms = volts / amperes. 3 volts / 0.300 amperes = 10 ohms.
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In a parallel circuit with a voltage source and several branch resistors, how is the total current related to the current in the branch resistors?
Each resistor added in parallel to the source draws some current ( in accordance with Ohm's Law, I = E / R ). The total current that the source must supply becomes the SUM of all these individual currents. Just like in your house, the total current drawn from the utility company is the sum of all the devices turned-on.
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Three resistors, respectively rated at 10, 15 and 20 ohms are connected in parallel across a 6-volt battery. Which statement is true?
key word: PARALLEL. In a parallel circuit, the total current is the sum of the currents. All resistors are subjected to the same voltage in a PARALLEL circuit. Ohm's Law tells us that the smaller resistor will draw more current than the others.
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Total resistance in a parallel circuit:
key word: PARALLEL. In a parallel circuit, each added resistor adds to the current drawn from the source. If more and more current is drawn, the total resistance must be going down. In PARALLEL, the total resistance is less than the smallest.
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Two resistors are connected in parallel and are connected across a 40 volt battery. If each resistor is 1000 ohms, the total current is:
Ohm's Law ( I = E / R ). Each resistor draws this much current: 40 volts divided by 1000 ohms = 0.040 amperes = 40 milliamperes. In PARALLEL, total current is the sum of the currents. Method B: identical resistors in parallel, total resistance is value divided by number. In this case, 1000 / 2 = 500 ohms. 40 volts / 500 ohms = 0.08 amperes = 80 milliamperes.
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The total resistance of resistors connected in series is:
key word: SERIES. In a series circuit, there is only one current. This current must wrestle with each resistor one after the other. In SERIES, total resistance is the sum of the resistances. The same current flows through all of them.
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Which series combination of resistors would replace a single 120 ohm resistor?
If ten resistors of equal value were wired in parallel, the total resistance would be:
key word: PARALLEL. In a parallel circuit with IDENTICAL resistors, total resistance is value divided by number. In this example, the value of one R divided by 10.
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The total resistance of four 68 ohm resistors wired in parallel is:
key word: PARALLEL. In a parallel circuit with IDENTICAL resistors, total resistance is value divided by number. In this example, 68 / 4 yields 17.
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Two resistors are in parallel. Resistor A carries twice the current of resistor B, which means that:
key word: PARALLEL. All resistors in a parallel circuit are subjected to the same voltage. Per Ohm's Law ( I = E / R, current = voltage divided by resistance ), if resistor A draws twice the current of resistor B, it must have half the resistance of Resistor B.
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The total current in a parallel circuit is equal to the:
key word: PARALLEL. In a parallel circuit, the total current is the sum of the currents. Each branch is subjected to the same voltage and draws a current in accordance with Ohm's Law ( I = E / R, current = voltage divided by resistance ).
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Why would a large size resistor be used instead of a smaller one of the same resistance?
Remember that power is voltage times current, P = E * I. A resistor dissipates power into heat. A resistor can only dissipate so much power without burning up: i.e., its power rating. Larger resistors can dissipate more heat.
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How many watts of electrical power are used by a 12 volt DC light bulb that draws 0.2 ampere?
P = E * I, power is voltage times current, watts = volts * amperes. 12 volts * 0.2 amperes = 2.4 watts [ VDC = volts in a Direct Current circuit ]
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The DC input power of a transmitter operating at 12 volts and drawing 500 milliamperes would be:
When two 500 ohm 1 watt resistors are connected in series, the maximum total power that can be dissipated by the resistors is:
This is about POWER RATING, not resistance. Two identical resistors can safely dissipate TWICE as much power as only one. [ Yes, total resistance will be twice as much, but that is immaterial here ]
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When two 500 ohm 1 watt resistors are connected in parallel, they can dissipate a maximum total power of:
This is about POWER RATING, not resistance. Two identical resistors can safely dissipate TWICE as much power as only one. [ Yes, total resistance will be half, but that is immaterial here ]
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If the voltage applied to two resistors in series is doubled, how much will the total power change?
P = E * I, power is voltage times current, watts = volts * amperes. Given the proportional relation of current versus voltage stated by Ohm's Law, if you double voltage in a circuit, current will double. Power is voltage times current, if both double, power has quadrupled ( 4 times more ).
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Which combination of resistors could make up a 50 ohms dummy load capable of safely dissipating 5 watts?
Four 200 ohms @ 2 watts in parallel = 50 ohms @ 8 watts. Two 25 ohms @ 2 watts in series = 50 ohms @ 4 watts. Ten 500 ohms @ 0.25 watts in parallel = 50 ohms @ 2.5 watts. Two 100 ohms @ 5 watts in series = 200 ohms @ 10 watts.
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A 12 volt light bulb is rated at a power of 30 watts. The current drawn would be:
The Power Law: P = E * I, power is voltage times current. Transformed to solve for I, it becomes I = P / E. In this example, I = 30 watts / 12 volts.
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If two 10 ohm resistors are connected in series with a 10 volt battery, the power consumption would be:
Two 10 ohm resistors in series present a total resistance of 20 ohms. Use Ohm's Law ( I = E / R ) to compute current as 10 volts divided by 20 ohms = 0.5 amperes. The Power Law: P = E * I, power is voltage times current. Power for this example becomes 10 volts times 0.5 amperes = 5 watts.
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One advantage of replacing a 50 ohm resistor with a parallel combination of two similarly rated 100 ohm resistors is that the parallel combination will have:
This is about POWER RATING, not resistance. Two identical resistors can safely dissipate TWICE as much power as only one. Two resistors of 100 ohms in PARALLEL yield a total resistance of 50 ohms ( In a parallel circuit with IDENTICAL resistors, total resistance is value divided by number ).
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Resistor wattage ratings are: