or
Amateur Extra Class (2016-2020)
Subelement E3
Section E3A
Electromagnetic waves; Earth-Moon-Earth communications; meteor scatter; microwave tropospheric and scatter propagation; aurora propagation
What is the approximate maximum separation measured along the surface of the Earth between two stations communicating by Moon bounce?
• 500 miles, if the Moon is at perigee
• 2000 miles, if the Moon is at apogee
• 5000 miles, if the Moon is at perigee
12,000 miles, if the Moon is visible by both stations

So long as both stations have a line of sight path to the moon, they can, in principle, communicate. The Earth’s circumference is about 24,000 miles, so half of that (12,000 miles) would have line of sight to the moon. In practice, the enormous path losses mean that high ERP, high gain antennas, low noise receivers and narrow bandwidth signals are required.

Memory Aid: Question asks what the “maximum” distance is - the answer is the one with the largest distance.

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What characterizes libration fading of an EME signal?
• A slow change in the pitch of the CW signal
A fluttery irregular fading
• A gradual loss of signal as the Sun rises
• The returning echo is several Hertz lower in frequency than the transmitted signal

This is caused by interference between the multiple path lengths of a moon bounce signal. The path lengths are constantly changing because the moon is “librating”. Although the moon does appear to always present the same face to the earth there is a small apparent “wobble” due to the fact that its orbit is not exactly circular. This apparent movement is called libration.

Because the moon has a highly irregular surface this rhythmic wobble causes irregular RF reflection.

The correct answer is the only one with "fading" in it.

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When scheduling EME contacts, which of these conditions will generally result in the least path loss?
When the Moon is at perigee
• When the Moon is full
• When the Moon is at apogee
• When the MUF is above 30 MHz

EME means Earth-Moon-Earth, or in other words, bouncing radio waves off of the Moon. Perigee means the point in the Moon's orbit where it is closest to the Earth.

When radio waves leave the antenna, they spread out, so when they travel far and spread out a lot, few waves hit someone else's antenna. This is much the same as a light bulb: when you're close to it, it's bright, and when you're far away, it looks dim.

The Moon is quite far away, so radio waves will spread out a lot before reaching the moon. When the Moon is at its closest point to Earth, the waves don't spread out quite as much as when the Moon is farther away. The difference between the perigee and apogee (farthest point) is about 40000 km, so round-trip is 80000 km or about 50000 miles. That means the trip is 50000 miles shorter when attempting a Moon bounce when the Moon is at perigee compared to when the Moon is at apogee.

This isn't necessarily the greatest cause for path loss for EME, but it is a factor.

Hint: Remember that apogee is farthest away from the earth, so perigee (think p for personal which is close) must mean the closest to earth, and thus should have the least loss in Earth-Moon-Earth (EME) communications.

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What do Hepburn maps predict?
• Sporadic E propagation
• Locations of auroral reflecting zones
• Likelihood of rain-scatter along cold or warm fronts
Probability of tropospheric propagation

William Hepburn runs a DX propagation website which includes "tropospheric ducting forecasts" and world maps.

http://www.dxinfocentre.com/tropo_wam.html

HINT - you might get a sunBURN in the Tropics.

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Tropospheric propagation of microwave signals often occurs along what weather related structure?
• Gray-line
• Lightning discharges
Warm and cold fronts
• Sprites and jets

Tropospheric propagation occurs when a difference in refractive indices in two adjacent pockets of air - for instance, at the intersection between warm and cold fronts - causes a radio wave to curve along the border between the two regions of air. This propagation is also called ducting. Hint: think about a duct between the fronts.

Memory tip: a microwave warms cold food.

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Which of the following is required for microwave propagation via rain scatter?
• Rain droplets must be electrically charged
• Rain droplets must be within the E layer
The rain must be within radio range of both stations
• All of these choices are correct

Here's a good explanation:

http://www.wa1mba.org/10grain.htm

The essential problem is that radio waves generally travel in a straight line until they're given a reason not to. Also, it turns out the Earth is round and virtually everyone you might want to talk to lives pretty close to the surface of that oblate spheroid.

Luckily, water droplets scatter some frequencies of radio waves in a similar way to how they scatter light. Water droplets collect and move in rain clouds above the surface of the Earth, so if you aim a directional antenna at rain, then you can get a signal to travel further away before it runs into the surface of the Earth. The receiving station just has to be able to see the same rain.

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Atmospheric ducts capable of propagating microwave signals often form over what geographic feature?
• Mountain ranges
• Forests
Bodies of water
• Urban areas

Evaporative ducts form over water where the cooling near the surface from evaporation results in cool air below warm air and a temperature inversion.

Silly hint: of the choices, water is the only substance you might put in your microwave. Silly 2- Ducts (ducks) love water.

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When a meteor strikes the Earth's atmosphere, a cylindrical region of free electrons is formed at what layer of the ionosphere?
The E layer
• The F1 layer
• The F2 layer
• The D layer

Meteor scatter propagation occurs via the E-Layer.

Briefly, the explanation of the signal - at least in the vicinity of 20 meters is forward scattering from ionization trails left behind by the myriads of tiny meteors which pepper the E region of the ionosphere at all times. Hence the maximum range for this form of transmission is essentially that for normal one-hop E-layer transmission, or 1500 miles.

Source: QST April 1953 (via NASA)

Memory tip: There are a lot of Es in "meteor" and "free electrons". Pick E-layer!

Another: Electrons go to the E-layer

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Which of the following frequency range is most suited for meteor scatter communications?
• 1.8 MHz - 1.9 MHz
• 10 MHz - 14 MHz
28 MHz - 148 MHz
• 220 MHz - 450 MHz

The best band for meteor scatter is the 50 MHz band, where contacts lasting for several seconds or even a minute or so can be made. At higher frequencies, the contacts will be of shorter duration.

There is only one range in the answer choices in which 50 MHz falls, and that is 28 MHz - 148 MHz.

Memory Trick: "Meteor" has six letters. The best band for meteor scatter is 6m. The only answer that covers the 6m band is 28-148MHz.

Additional Memory Trick: MSK144 is a meteor scatter mode. 144MHz is only in the correct answer.

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Which type of atmospheric structure can create a path for microwave propagation?
• The jet stream
Temperature inversion
• Wind shear
• Dust devil

A temperature inversion traps a layer of warm air above and below layers of cold air The microwave signal travels in this layer of warm air, similar in concept to how a microwave signal travels in a wave guide.

Hint: A microwave heats the temperature of food.

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What is a typical range for tropospheric propagation of microwave signals?
• 10 miles to 50 miles
100 miles to 300 miles
• 1200 miles
• 2500 miles

Tropospheric scatter (also known as troposcatter) is a method of communicating with microwave radio signals over considerable distances from 100 to 300 miles depending on terrain and climate factors. This method of propagation uses the tropospheric scatter phenomenon, where radio waves at UHF and SHF frequencies are randomly scattered as they pass through the upper layers of the troposphere. Radio signals are transmitted in a narrow beam aimed just above the horizon in the direction of the receiver station. As the signals pass through the troposphere, some of the energy is scattered back toward the Earth, allowing the receiver station to pick up the signal.

Silly trick to help remember: We heat most meals in a microwave between 1 and 3 mins (1:00 and 3:00) so choose 100 to 300.

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What is the cause of auroral activity?
• The interaction in the F2 layer between the solar wind and the Van Allen belt
• A low sunspot level combined with tropospheric ducting
The interaction in the E layer of charged particles from the Sun with the Earth's magnetic field
• Meteor showers concentrated in the extreme northern and southern latitudes

The Aurora Borealis is actually the result of collisions between gaseous particles in the Earth's atmosphere with charged particles released from the sun's atmosphere. Variations in colour are due to the type of gas particles that are colliding.

Source: Northern Lights Centre

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Which emission mode is best for aurora propagation?
CW
• SSB
• FM
• RTTY

The cause of auroral activity—sometimes called the Northern Lights or aurora borealis—is the interaction in the E layer of charged particles from the Sun with the Earth's magnetic field. CW is the emission mode that is best for aurora propagation.

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From the contiguous 48 states, in which approximate direction should an antenna be pointed to take maximum advantage of aurora propagation?
• South
North
• East
• West

In the northern hemisphere, your best chance to find an aurora is toward the magnetic north pole. If you were in the southern hemisphere, you would seek auroras toward the magnetic south pole.

In the Northern hemisphere the charged particles from the sun are funnelled in the direction of the north pole. This is where any aurora will be located. Aurora do not need to be visible to be useful for radio propagation.

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What is an electromagnetic wave?
• A wave of alternating current, in the core of an electromagnet
• A wave consisting of two electric fields at parallel right angles to each other
A wave consisting of an electric field and a magnetic field oscillating at right angles to each other
• A wave consisting of two magnetic fields at right angles to each other

Classically, electromagnetic radiation consists of electromagnetic waves, which are synchronized oscillations of electric and magnetic fields that propagate at the speed of light through a vacuum. The oscillations of the two fields are perpendicular to each other and perpendicular to the direction of energy and wave propagation, forming a transverse wave. Electromagnetic waves can be characterized by either the frequency or wavelength of their oscillations to form the electromagnetic spectrum.

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Which of the following best describes electromagnetic waves traveling in free space?
• Electric and magnetic fields become aligned as they travel
• The energy propagates through a medium with a high refractive index
• The waves are reflected by the ionosphere and return to their source
Changing electric and magnetic fields propagate the energy

Remember all the way back to the Technician-level theory, where you learned that radio waves have an electric and magnetic component. And those electric and magnetic fields are changing because the radio signals are alternating current (and alternating pretty fast too!).

The electric and magnetic fields are 90 degrees apart, always, so they don't become aligned.

Refraction doesn't describe traveling in free space.

If the waves are traveling in free space there is nothing that would cause them to return to their source.

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What is meant by circularly polarized electromagnetic waves?
• Waves with an electric field bent into a circular shape
Waves with a rotating electric field
• Waves that circle the Earth
• Waves produced by a loop antenna

In electrodynamics, circular polarization of an electromagnetic wave is a polarization in which the electric field of the passing wave does not change strength but only changes direction in a rotary manner.

https://en.wikipedia.org/wiki/Circular_polarization

Memory aid: circularly: like a wheel rotating

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