Basic Electrical Theory
Basic Electrical Theory
Power calculations
A transmitter power amplifier requires 30 mA at 300 volt. The DC input power is
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The DC input power of a transmitter operating at 12 volt and drawing 500 milliamp would be
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When two 500 ohm 1 watt resistors are connected in series, the maximum total power that can be dissipated by both resistors is
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When two 1000 ohm 5 watt resistors are connected in parallel, they can dissipate a maximum total power of
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The current in a 100 kilohm resistor is 10 mA. The power dissipated is
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A current of 500 milliamp passes through a 1000 ohm resistance. The power dissipated is
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A 20 ohm resistor carries a current of 0.25 ampere. The power dissipated is
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If 200 volt is applied to a 2000 ohm resistor, the resistor will dissipate
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The power delivered to an antenna is 500 watt. The effective antenna resistance is 20 ohm. The antenna current is
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The following two quantities should be multiplied together to find power
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The following two electrical units multiplied together give the unit "watt"
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The power dissipation of a resistor carrying a current of 10 mA with 10 volt across it is
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If two 10 ohm resistors are connected in series with a 10 volt battery, the battery load is
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Each of 9 resistors in a circuit is dissipating 4 watt. If the circuit operates from a 12 volt supply, the total current flowing in the circuit is
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Three 18 ohm resistors are connected in parallel across a 12 volt supply. The total power dissipation of the resistor load is
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A resistor of 10 kilohm carries a current of 20 mA. The power dissipated in the resistor is
By convention, \(P\) is power, \(I\) is current, \(R\) is resistance, and \(E\) is Voltage (Electro-motive force).
The Power Law states: \(P = I \times E\). Ohm's law states that \(E = I \times R\). Combining those to remove E, we get a restatement of the Power Law as \(P = I \times (I \times R)\), or \(P = I^2 \times R\)
So in this case:
\[P = (.02)^2 \times 10,000\] \[P = 0.0004 \times 10,000\]
Thus
\[P = 4 \text{ watts}\]
Last edited by kd7bbc. Register to edit
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A resistor in a circuit becomes very hot and starts to burn. This is because the resistor is dissipating too much
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A current of 10 ampere rms at a frequency of 50 Hz flows through a 100 ohm resistor. The power dissipated is
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The voltage applied to two resistors in series is doubled. The total power dissipated will
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