The Radio Transmitter
The Radio Transmitter
Transmitter Theory
Morse code is usually transmitted by radio as
Correct answer: an interrupted carrier
Morse code is transmitted using continuous wave (CW) transmission by switching the transmitter carrier on and off in accordance with the dots and dashes of the code.
This produces a radio-frequency carrier that is present during key-down and absent during key-up.
Therefore, Morse code is usually transmitted as an interrupted carrier.
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To obtain high frequency stability in a transmitter, the VFO should be
Correct answer: powered from a regulated DC supply
A VFO (Variable Frequency Oscillator) must operate under stable conditions to maintain a constant output frequency.
Variations in supply voltage can cause changes in the oscillator’s operating point, leading to frequency drift.
Using a regulated DC supply helps maintain a constant voltage and improves frequency stability.
Therefore, the VFO should be powered from a regulated DC supply for high frequency stability.
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SSB transmissions
Correct answer: occupy about half the bandwidth of AM transmissions
Single Sideband (SSB) transmission uses only one sideband and suppresses the carrier.
In conventional AM:
So the bandwidth is:
\[ B_{\text{AM}} = 2 f_m \]
In SSB:
\[ B_{\text{SSB}} = f_m \]
Thus:
\[ B_{\text{SSB}} = \frac{1}{2} B_{\text{AM}} \]
Therefore, SSB transmissions occupy about half the bandwidth of AM transmissions.
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The purpose of a balanced modulator in a SSB transmitter is to
Correct answer: suppress the carrier while producing two sidebands
A balanced modulator combines the audio signal with the RF carrier in a way that cancels the carrier component at its output while still producing both the upper and lower sidebands. The result is a double sideband suppressed carrier (DSB-SC) signal.
This is the required first step in generating an SSB signal. A filter or phasing network later removes one of the sidebands.
Therefore, the purpose of a balanced modulator is to suppress the carrier while producing two sidebands.
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Several stations advise that your FM simplex transmission in the "two metre" band is distorted. The cause might be that
Correct answer: A — the transmitter modulation deviation is too high
In FM (frequency modulation), the audio signal causes the carrier to deviate above and below its centre frequency. The maximum permitted deviation for narrow-band FM in the 2 m amateur band is typically ±5 kHz. If the deviation is set too high — often caused by the microphone gain or audio drive level being too high — the signal occupies excessive bandwidth and adjacent receivers cannot decode it cleanly, producing distortion (sometimes called "over-deviation" or "splatter"). Other stations hear the transmission as harsh or unintelligible.
Therefore, distorted FM audio reported by multiple stations is a classic symptom of excessive modulation deviation, and the cure is to reduce the microphone gain or audio drive level on the transmitter.
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The driver stage of a transmitter is located
Correct answer: before the power amplifier
In a transmitter, the driver stage provides sufficient signal power to properly drive the final power amplifier stage.
The typical signal chain is:
Oscillator → Buffer → Driver → Power Amplifier → Output Filter → Antenna
Therefore, the driver stage is located before the power amplifier.
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The purpose of the final amplifier in a transmitter is to
Correct answer: D — increase the power fed to the antenna
The final amplifier (also called the power amplifier or PA) is the last active stage in a transmitter chain. Its role is to boost the RF signal to a level sufficient to drive the antenna with the desired transmit power. All earlier stages operate at relatively low power levels; the final amplifier raises that power to the rated output of the transmitter.
Therefore, the final amplifier's sole purpose is to increase the RF power delivered to the antenna to the required transmit level.
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The difference between DC input power and RF power output of a transmitter RF amplifier
Correct answer: is dissipated as heat
An RF power amplifier converts DC input power into RF output power, but this process is not 100% efficient.
The difference between the DC input power and the RF output power is the power lost due to inefficiencies in the amplifier, such as:
This lost power is converted into heat within the amplifier components.
Therefore, the difference is dissipated as heat.
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The process of modulation allows
Correct answer: information to be impressed on to a carrier
Modulation is the process of combining an information signal (such as voice or data) with a high-frequency carrier wave.
This allows the information to be transmitted efficiently over long distances.
Therefore, modulation allows information to be impressed on to a carrier.
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The output power rating of a linear amplifier in a SSB transmitter is specified by the
Correct answer: C — peak envelope power
For a Single Sideband (SSB) transmitter, the standard way to rate the output power of a linear amplifier is Peak Envelope Power (PEP). SSB signals have no constant carrier — the instantaneous power varies with the voice modulation. PEP is measured at the peak of the RF envelope, representing the highest power the amplifier must deliver during a modulation peak. This is the most meaningful rating for a linear amplifier handling SSB, as it defines the headroom required to avoid distortion on speech peaks.
\[ P_{PEP} = \frac{V_{peak}^2}{2R} \]
where \(V_{peak}\) is the peak envelope voltage and \(R\) is the load impedance.
Therefore, the output power of a linear amplifier in an SSB transmitter is correctly specified by the peak envelope power (PEP), which captures the maximum instantaneous RF output at modulation peaks.
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